kotlin键值对数组

Given an array, we have to sort its elements in ascending order.

给定一个数组，我们必须按升序对其元素进行排序。

Example:

例：

Input:    arr = [10, 20, 5, 2, 30]    Output:    sorted array (Ascending Order): [2, 5, 10, 20, 30]

在Kotlin中以升序对数组进行排序的程序 (Program to sort an array in ascending order in Kotlin)

package com.includehelp.basicimport java.util.*//Main Function entry Point of Programfun main(args: Array
    
     ) {    //Input Stream    val s = Scanner(System.`in`)    //Input Array Size    print("Enter number of elements in the array: ")    val size = s.nextInt()    //Create Integer array of Given size    val intArray = IntArray(size)    //Input array elements    println("Enter Arrays Elements:")    for (i in intArray.indices) {        print("intArray[$i] : ")        intArray[i] = s.nextInt()    }    //to Perform Ascending Order Sorting on integer Array    var temp:Int    for (i in intArray.indices) {        for (j in i + 1 until intArray.size) {            if (intArray[i] > intArray[j]) {                temp = intArray[i]                intArray[i] = intArray[j]                intArray[j] = temp            }        }    }    //Alternatively we can also use sort() method of Arrays     //Class in kotlin to sort in Ascending Order    //intArray.sort()    print("Ascending Order: ")    for (item in intArray) {        print("$item ")    }}
    

Output

输出量

Enter number of elements in the array: 6Enter Arrays Elements:intArray[0] : 5intArray[1] : 23intArray[2] : 1intArray[3] : 0intArray[4] : 9intArray[5] : 76Ascending Order: 0 1 5 9 23 76----------------Enter number of elements in the array: 8Enter Arrays Elements:intArray[0] : 45intArray[1] : 3intArray[2] : 89intArray[3] : -8intArray[4] : -45intArray[5] : 0intArray[6] : 432intArray[7] : 6Ascending Order: -45 -8 0 3 6 45 89 432

翻译自:

kotlin键值对数组